# a person was climbing on a building. He slips 1m for every 5m he climbs up. If the building is 53m high and he takes 5 seconds to climb 1m, find the total time taken by him to get on the top of the building..

THE PERSON CLIMBS 5m AND SLIPS 1m
​TO CLIMB Im HE TAKES 5 SECONDS
SO FOR 5m HE TAKES 5x5= 25 SECONDS
AS HE SLIPS 1m FOR EVERY 5m CLIMB
IN EACH ATTEMPT HE CLIMBS 5-1=4 m in 25 SECONDS
TOTAL HEIGHT OF THE BUILDING= 53m
​SO HE WILL NEED 53/4= 13 (remainder 1 ignored as he will not slip after the last climb)
SO, TIME TAKEN TO CLIMB THE BUILDING = 25x13=325 SECONDS
ANS:: 325 SECONDS

• 11
it takes him 5*5=25 seconds to climb 5-1=4 meters.

So, his rate of ascent is 4/25 m/s

It will take him 53/(4/25) = 1325/4 = 331.25 seconds to make the climb.

If the climb has to be broken into discrete chunks of 5m each, then things change some.
• -2
325 seconds
• 5
4 metres
• 3
325sec
• 4
The answer is 325
• 2
325 seconds, as
1m slipped for every 5m climbed. Building height is 53m. He takes 5 seconds to climb every 1m.
So, 5x5=25 seconds, 5-1=4,
so, the rate of ascent is 25seconds per 4m. So, 53/4=13 (The remainder is ignored as he OBVIOUSLY won't slip at the last step.)
SO, 13x25 = 325!
Hope you found the explanation heplful!
• 12
the anser is 325 sec

• 0
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