A piece of land is240 m long and 120 m wide, has two roads in its centre of equal width - Maths - Perimeter and Area

Question

A piece of land is240 m long and 120 m wide, has two roads in its
centre of equal width 2 5 m One road is parallel to length and
other is parallel to its width Find the area of roads and also find
the cost of planting the grass at the rate of Rs 10 per sq m

Manbar Singh · Accepted Answer

Dear Student,

Area of road EFGH = EF × FG=240 × 2
5 = 600 m2Area of road  KLMN = KL ×LM=2
5 × 120=300 m2Area of square PQRS = side2 = 2
52 = 6
25 m2Now, area of cross roads = Area of road EFGH + Area of road  KLMN - Area of square PQRS=600 + 300 - 6
25=893
75 m2Area of the land where the grass is to be planted = area of ABCD - area of cross roads=AB×BC - 893
75=240×120 - 893 75=28800-893 75=27906
25 m2Cost of planting the grass in 1 m2 area = Rs 10Cost of planting the grass in 27906
25 m2 area = Rs 10 × 27906
25 = Rs 279062 50

Regards

. A piece of land is240 m long and 120 m wide, has two roads in its centre of equal width 2.5 m. One road is parallel to length and other is parallel to its width. Find the area of roads and also find the cost of planting the grass at the rate of Rs. 10 per sq.m