a point is equidistant from A(-6,4) and B(2,-8).find its coordinates if the abscissa and ordinate are equal.

Let coordinates of ‘P’ be (x, x).

A (-6, 4) and B (2, -8)

Since PA = PB

PA2= PB2
 
Using distance formula,

(x+6)2+ (x-4)2= (x-2)2+(x+8)2x2+36+12x +x2 +16-8x =x2+4-4x +x2+64 +16x2x2+4x+52 = 2x2+12x+684x-12x = 68-52-8x =16x=-168=-2


 
Therefore, the coordinates of P are (-2, -2)

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