A pole of height h=50 ft has a shadow of length i=50 ft at a particular instant time Find the angle of elevation(in degrees) of the sun at this point of time.The image is given below.

h=i
tan A = BC
             AB
          = h
             i
          = h
              h
tan A = 1
tan A = tan 45o
∠ A = 45o
 

  • 2
Ans is 45 degrees
Because apply tanteeta
  • 1
angle A = 450
 
  • 1
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