A rectangular loop of wire of size      2cm X 5 cm carries a steady current of 1 A. A straight long wire carrying a current is kept near the loop as shown in figure . If the loop and the wires are coplanar, find the direction of force on the loop due to the current carrying wire

Dear Student
As in your question figure is missing so i am considering below figure to solve the question
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We know FB  =i  l  ×  B   On line AB and CD magnetic forces are equal and opposite. So they cancel out each other.  Magnetic force on line AD isFB  =i  l  ×  B  = ilBB=μoI2πrF=μoil I2πr (Attractive)Magnetic force on line CB.F'=ilB'B'=μoI2πr'F'=μoil I2πr' (Repulsive)Force acting on loop F=μoiI2πl 1r-1r'Nowi= 4AI=1Ar= 1 cm r' = 1+2 = 3cmL= 5cmF=2×10-7×4×1×0.05110-2-13×10-2 =26.66×10-7 N

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