A's income is 20 % less than that of B's. How much per cent is B's income more than A's ? Solve it by two methods. First by 100. Second by taking "x"?

Suppose B's income is x.
Now, A's income is 20 % less than that of B's.
So, A's income = x-x×20100 = x-x5 = 4x5
Then, difference between A's income and B's income = x-4x5 = x5
So, B's income is x5 more than A's income.
Therefore required percentage = x5×1004x5 = x5×54x×100 = 25%
Therefore B's income is 25% more than A's income.

Second method:
Suppose B's income is 100.
Now, A's income is 20 % less than that of B's.
So, A's income = 100-100×20100 = 100-20= 80
Then, difference between A's income and B's income = 100-80 = 20
So, B's income is 20 more than A's income.
Therefore required percentage = 20×10080 = 25%
Therefore B's income is 25% more than A's income.

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