A satellite is revolving around the earth at a height h. The satellite explodes into two equal parts, one part has zero velocity after the explosion, and the other moves in the same direction with double the orbital speed of the original satellite. The maximum height reached by the part with double the velocity is (Neglect the gravitational effects between the fragments)
(A) 3h + 4R (B) 3R + 4h
(C) 3(R +h) (D) none of these
Dear student
let initial the satellite has mass M and mass of earth is m ,
initially the satellite is at distance r= h+R (from the centre of earth)and when it reaches the maximum height its distance is r0 from centre of earth hence r0 =R+H (here H is height from surface of earth)
Regards
let initial the satellite has mass M and mass of earth is m ,
initially the satellite is at distance r= h+R (from the centre of earth)and when it reaches the maximum height its distance is r0 from centre of earth hence r0 =R+H (here H is height from surface of earth)
Regards