A ship is at a distance of 560 m from a fort defending the harbour entrance of an island. A defence cannon, located at sea level, fires balls at initial speed u 82 m/s.
(a) At what angle 0 from the horizontal, must a ball be fired to hit the ship?

(b) How far should the ship be from the cannon, if it is to be beyond the maximum range of the cannon balls?

Dear Student,Given,R=560m, u=82m/si)The horizontal range is,R=u2sin2θg560=82×82×sin2θ9.8=686.14×sin2θsin2θ=560686.14=0.8162θ=sin-10.816=54.700θ=27.350Ball must be fired at an angle θ=27.350ii)The maximum range of the cannon ball will be when θ=450Rcannon=u2sin2θg=82×82×sin9009.8=686.12mAt this range the cannon ball will hit the ship.So the ship should be at a distance >686.12mRegards.

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