a straight line with slope 1 passes through Q (3,5) and meets the straight line x+ y- 6=0 at P find distance PQ

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Please find below the solution to the asked query:

Slope of line passing through Q3,5 ism1=1Slope of given x+y-6=0 ism2=-Coefficient of xCoefficient of y=-1As m1×m2=-1, hence lines are perpendicular to each other.PQ is perpendicular distance of point Q3,5 from x+y-6=0PQ=3+5-612+12=22=2  Hence Proved

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