A student prepared a saturated solution of ‘P’ at 315K and then added 60g water to it. What mass of ‘P’ must be added to again make the saturated solution?

Solution: 

Considering 100 g of water at 315 Kcontain salt = 40 g160 g of water at 315 Kcontain salt = 40100×160 = 64 gMass of the salt to be added to make the solution saturated again = 64-40 = 24 g

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