A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceeration is uniform. Find the acceleration and the distance traveed by the train for attaining this velocity.

u=0

v=72 km/h=20 m/s

t=5 mins=300s

a=v-u/t

=20-0/300

=20/300

=1/15

s=ut+1/2at2

=0*300+1/2*1/15*300*300

=0+20*150

=3000m

=3 km