A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceeration is uniform. Find the acceleration and the distance traveed by the train for attaining this velocity.
u=0
v=72 km/h=20 m/s
t=5 mins=300s
a=v-u/t
=20-0/300
=20/300
=1/15
s=ut+1/2at2
=0*300+1/2*1/15*300*300
=0+20*150
=3000m
=3 km