A uniform electric field E of 300N/C is directed along PQ. A(4,1) , B(4,4) and C(-3,4) are three points in the field having X and Y(in metres). Calculate potential difference between the points i)A and B ii)B and C

(i)Distance between A and B:d=4-42+4-12   =3 mPotential difference:V=Ed   =300 × 3   =900 volts(ii)Distance between A and B:d=-3-42+4-42   =7 mPotential difference:V=Ed   =300 × 7   =2100 volts

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