A wheel of 16 kg mass and 50 cm radius is pulled
by a force of 8 N applied on the string wound onthe wheel suspended at S. Angular speed of thewheel after 10 s
r = 50*10-2m
m=16 kg
F = 8N
By Newton's second law, F=ma
Therefore, 8=16*a
a = 0.5 m/s2
v=u+at
v=0+0.5*10
v=5m/s
angular velocity = v/r
=5/0.5
10 rad/s
m=16 kg
F = 8N
By Newton's second law, F=ma
Therefore, 8=16*a
a = 0.5 m/s2
v=u+at
v=0+0.5*10
v=5m/s
angular velocity = v/r
=5/0.5
10 rad/s