a wire is (7x-3) metres long.a length of (3x-4)meter is cut for use now ans the question if this left out wire is used for making an equilateral triangle what is the lengthof each side of the triangle so formed Share with your friends Share 4 Varun.Rawat answered this Total length of the wire = 7x-3 mtsLength of the wire that is cut = 3x-4 mLength of the wire left = 7x-3 - 3x-4 = 7x-3-3x+4 = 4x+1 mNow, perimeter of equilateral ∆ = 4x+1 m⇒3s = 4x+1 where s = length of each side of an equilateral ∆⇒s = 4x+13 mLength of each side of an equilateral ∆ =4x+13 m -1 View Full Answer Dev Patel answered this Just started -1 Dev Patel answered this de -2 Jegannathan Anandaraman answered this Hello Ramandeep, initial length = 7 x - 3 Length cut out = 3 x - 4 So left out length = 7 x - 3 -( 3x - 4) = 7 x - 3 - 3x + 4 = 4x + 1 Now as equilateral triangle of length a is formed with this length 4x + 1 then a = 1/3 * (4x + 1) = 4/3 * x + 1/3 -1
