a wire of 5.8 metre long,2 millimetre diameter carries 750 milliampere current when 22 mV potential difference is applied at its ends if drift speed of electrons is found 1.7 into 10^-5 metre per second then find current density and number of free electrons per unit volume answer- current density=2.4*1)^5A/m square n=8.8*10^28 Share with your friends Share 13 Vaibhav Tiwari answered this Dear Student, length, l=5.8 mdiameter, d=2 mm=2×10-3 mradius, r=1×10-3 mcurrent, I=750 mA=750×10-3 Apotential difference, V=22 mV=22×10-3 Vdrift speed, vd=1.7×10-5 m/scurrent density, J=IAarea, A=πr2A=3.14×1×10-32=3.14×10-6 m2J=750×10-33.14×10-6=2.38×105 A/m2vd=Jnen=Jvden=2.38×1051.7×10-5×1.6×10-19=8.7×1028 21 View Full Answer