Aarav is 3 years younger than his sister keya. if the sum of their ages is 27 years, what are the present ages?

Let Keya's age be x
then aarav's age will be x-3
sum of their ages =27
                                =x+(x-3)=27
                                =x+x-3=27
                                =2x-3=27
                                =2x=27+3
                                =2x=30
                                =x=30/2
                                =x=15
therefore Keya is 15 years old
Aarav's age=x-3
                   =15-3
                   =12

  • 5
aarav=x
keya=x+3
sum=27
=2x+3=27
=2x=24
x=12
=aarav=12
and keya= 15
  • 0
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