AB is a chord of a circle with radius ‘r’. If P is any point on the circle such that ∠APB is a right angle , then AB is equal to ??
how to solve this question & plz tell the method for solving

it is the converse of the theorem"angle in the semicircle is a right angle triangle" so then diameter=2r

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Obviously AB is equal to 2r because diameter is the only chord which makes 90 degree on any point inside the circle
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