ABC and DBC are both isosceles tringles on a common base BC such that A and D lie on the same side of Bc. Are triangles ADB and ADC congruent? Which condition do you use? If angle BAC = 40 degrees and angle BDC = 100 degrees then find angle ADB
Given: 2 triangles ABC and BDC having common base BC,
AB = BD,
AC = CD
Consider ΔABC and ΔBCD,
AB = BD (given)
BC = BC (common)
AC = CD (given)
∴ ΔABC ΔDBC,by SSS congruency
Hence, ∠1 = ∠2 and ∠3 = ∠4 (cpct)
⇒ ∠5 = ∠6
But ∠ABD may or may not be equal to ∠ACD.