# abc is a triangle and ab=bc and bp-bq show that ap=cq using euclids axiom or postulates.

AP+BP=AQ+CQ

(BY AXIOM 3 THINGS WHICH R EQUAL TO ONE ANOTHER IS EQUAL TO ONE ANOTHER)

AP+BP-BP=AQ+CQ-AQ

AP=CQ

HENCE PROVED

AP+BP=AQ+CQ

(BY AXIOM 3 THINGS WHICH R EQUAL TO ONE ANOTHER IS EQUAL TO ONE ANOTHER)

AP+BP-BP=AQ+CQ-AQ

AP=CQ

HENCE PROVED

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