ABCD is a  cyclic quadrilateral and AB=AC,if <ACB=70* find < BDC

Given : AB=AC 
<ACB = <ABC  ( angle opposite to equal side is equal)
<ABC = 70 *
Using angle  sum property in Triangle ABC 
<BAC +<ACB+<ABC = 180
<BAC +70 +70 = 180
<BAC = 40

<BAC + <BDC = 180  ( angles of cyclic quadrilateral is supplementary )
40 + <BDC =180
<BDC = 140

  • 10
What are you looking for?