ABCD is a rhombus.show that diagonal AC bisects angle A as well as angle C and diagonal BD bisects angle B as well as angle D?

sir/maam kindly tell me how to solve this question with proper steps?

Given:ABCD is a Rhombus

SO AB=BC=CD=AD

to prove:angle BAC=angle DAC

AND angle DCA=angle BCA

Solution: in triangles ADC and ABC

AB=AD (given)

CD=CB(given)

AC is common

so triangle ADC is congruent to triangle ABC

SO

angle BAC= angle DAC (cpct)

angle DCA= angle BCA (cpct)

HENCE PROVEN

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