After impact the string rotates through an angle 120 degrees ,find the velocity when the block ceases to perform circular motion.

Dear student,


velocity of bullet at highest point is =ucosθby momentum  conservationmucosθ=mucosθ2+Mvv=mucosθ2M  intial velocity of block.by energy conservation we can find the velocity at point where circular motion ceases.Mv22=Mgl+lsin30+Mv'22v22=gl+lsin30+v'22v22-gl+lsin30=v'22v2-2gl+lsin30=v'2v'=mucosθ2M2-3gl  this is the velocity of block at 120 degreeRegards

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