# All kings ,queens and aces are removed from a pack of 52 cards . The remaining cards are well shuffled and a card is drawn from it . Find the probability that the drawn card is (A) a black face card (B) a red card

Total no. of Queens, kings and aces in a deck of 52 cards = 12

Now Total Outcomes = 52 - 12 = 40

a) Probability of a Black Face Card = 2/40 = 1/20 ( Since 2 Jacks of Black are still remaining)

b) Probability of a Red Card = 20/40 = 1/2 [ Since overall six cards of red are removed i.e. Queen, King and Ace of  ♥(Hearts) ♦(Diamonds)]

• 39

(A) 4/40

• -7

Total outcomes  =  44

{A} let E1 be the probability of getting a black face card.

P{E1} = 2/ 44  =  1 / 22

[B] let E2 be the probability of getting a red card.

P{E2} = 11/ 44  =  1/4

• -6

Total outcomes = 44

{A} let E1 be the probability of getting a black face card.

P{E1} = 2/ 44 = 1 / 22

[B] let E2 be the probability of getting a red card.

P{E2} = 22/ 44  = 1 /2

• -7

Total no. of Queens, kings and aces in a deck of 52 cards = 12

Now Total Outcomes = 52 - 12 = 40

a) Probability of a Black Face Caed =  2/40 = 1/20 ( Since 2 Jacks of Black are still remaining)

b) Red face card = 2/40 = 1/20 ( Since 2 Jacks of Red are still remaining)

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Total outcomes = 40

{A} let E1 be the probability of getting a black face card.

P{E1} = 2/ 40 = 1 / 20

[B] let E2 be the probability of getting a red card.

P{E2} = 20/ 40 = 1 /2

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