# an archery target has 3 regions formed by three concentric circles. if the diameters of the concentric circles are in the ratio 1:2:3, then find the ratio of the areas of the regions??? guys plz help me....need this answer before 10:30 am today... Pretty Easy... Hope you got that.. :)

• 108
Then the radii are d/2, d, 3d/2
The area of the central circle = pi.d^2/4
The area of the next region = pi (d^2 - d^2/4) = (3/4)pi.d^2
The area of the outermost region = pi (9d^2/4 - d^2) = (5/4)pi.d^2
Cancel out the 1/4ths
So the ratios of their areas are: 1:3:5
• -11
whattttt
• -20
Then the radii are d/2, d, 3d/2
The area of the central circle = pi.d^2/4
The area of the next region = pi (d^2 - d^2/4) = (3/4)pi.d^2
The area of the outermost region = pi (9d^2/4 - d^2) = (5/4)pi.d^2
Cancel out the 1/4ths
So the ratios of their areas are: 1:3:5
• -5  • 1
1:3:5
• -12
1:3:5
• -9
I need perimeter of the areas
• -15
Best ans if you see this you will top the board exam • -44
Let take the first season BX and second is a b y and third reason be love love love and Archi targeted has three reason for why 3 concentrated circle as shown in figure 5 if the diameter of the constituent circle are in the ratio 4 is to 2 is to 3 then find the ratio of areas of these reasons other Aap Ko Agar acha laga ho to like kare share Kare Kare if you love like this
• 1
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