An electron after being accelerated through a potential difference of 104 Volt enters a uniform magnetic field of 0.04T perpendicular to its direction of motion.Calculate the radius of curvature of its trejectory?

The method proposed by kushal1122 is correct. One obtains a formula for radius of the path,

r =

=> r = 8.43 X 10-3 m

@ kushal: Good work! keep posting!

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use qv = kinetic energy 

and find the value of velocity so attained 

then magnetic force equals to centripital force 

that is   qVxB = mV2/R 

R = mV/qB

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