An elevator can carry a maximum load of 1800kg, is moving up with a constant speed of 2m/s The - Physics - Work Energy And Power

Question

An elevator can carry a maximum load of 1800kg, is moving up
with a constant speed of 2m/s The frictional force opposing the
motion is 4000N Determine the minimum power delivered by the motor
to the elevator in watts (take g=9 8m/s2

Satyendra Singh · Accepted Answer

Weight in the elevator = mgw = 1800×9
8w = 17640 Ntotal force acting downwards = weight + frictional forceF = w +fF = 17640 + 4000F = 21640 NNow,power delivered by the motor = Force × VelocityP = F × vP = 21640 × 2P = 43280 Watts

An elevator can carry a maximum load of 1800kg, is moving up with a constant speed of 2m/s. The frictional force opposing the motion is 4000N. Determine the minimum power delivered by the motor to the elevator in watts. (take g=9.8m/s2

An elevator can carry a maximum load of 1800kg, is moving up with a constant speed of 2m/s. The frictional force opposing the motion is 4000N. Determine the minimum power delivered by the motor to the elevator in watts. (take g=9.8m/s²