An elevator descend into a mine shaft at the rate of 6 m/min If it begins to descend from - Maths - Integers

Question

An elevator descend into a mine shaft at the rate of 6 m/min If it
begins to descend from 20 m above the ground ,what will be its
position after 45 minutes?

Kavita Verma · Accepted Answer

Dear Student,

distance travelled by elevator in 1 min = 6 mdistance travelled by elevator in 45 min = 6×45 = 270 mBut it began to descent from 20 m above the ground
Therefore distance travelled below the ground = 270 - 20 = 250 m

Regards,

An elevator descend into a mine shaft at the rate of 6 m/min. If it begins to descend from 20 m above the ground ,what will be its position after 45 minutes?