An Equi-convex lens of glass (R.I = 1.5) of focal length 10cm is silvered on one side. Then it will behave like ?
[Answer: concave mirror of F.L. = 2.5cm]
Send the solution by using formula of 1/F net = -2/F lens + 1/F mirror

Dear Student,
μ=1.5f=R1=R2=10cmpower of the combination,P=2PL+PM-1F=2μ-11R1-1R2-2R2-1F=21.5-1110-1(-10)-2(-10)-1F=2×0.5×210+210=210+210=410F=-104=-2.5cmthe system behaves like concave mirror of focal length 2.5cm.
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