An equilateral prism of glass of refractive index of 1.45 is immersed in water of refractive index 1.33. A narrow beam of light falls normally on one face of the prism. find the angle of emergence of the beam??

Question

An equilateral prism of glass of refractive index of 1 45 is
immersed in water of refractive index 1 33 A narrow beam of light
falls normally on one face of the prism find the angle of emergence
of the beam??

Jyoti Pant · Accepted Answer

Angle of incidence, i=00nw=1 33ng=1
45gnw=Refractive index of glass w r
t water=1 451 33=1
09Angle of prism=600sin 00sin r1==1
09sin r1=0or r1=00Also, we know that A= r1+ r2or  r2=A- r1=600-00=600Again,sin r2sin e=11
09sin e=1 09×sin r2=1 09×sin 600=0
94e=sin-1(0 94)