An iron sphere of radius 'a' units is immersed completely in water contained in aright circular cone of semi vertical angle 30 degree ,water is drained off from the cone till it's surface toches the sphere.Find the volume of water remaining in cone.

pls help me frnds

find the surface area of a cube whose edge=15 cm?

give me answer

 height of cone = h

sin 30 = a/h

1/2 = a / h

h = 2a

vol = 1/3 pi a2 x 2a

a frustum will be formed when immersed

r of frustum be a and radius of sphere

height of frustum of diameter of sphere

rest u do by yourself

SA of cube = 6 x 15 x 15 = 1350 cm2

raghu here how sin 30 = a/h

sin 30 = a / l where l is the slant height on the point of contact of sphere and cone 

no buddy.....l is tangent so it the angle it subtends = 90

height is the opp side that is hypotenuse...hence i used sin 30 ....can u understand now.....