an object A moving horizontally with kinetic energy of 800 J experiences a constant horizontal opposing force of 100 N - Physics - Motion In A Plane

Question

an object A moving horizontally with kinetic energy of 800 J
experiences a constant horizontal opposing force of 100 N while
moving from point X to point Y where XY =2 m what is the energy of
A at Y ? In what further distance will A come to rest if this
opposing force continues to act on it ?

Alisha Shah · Answer

1 work = force X distance= 100 X 2 = 200 N
' net energyof object = 800 - 200 = 600N
2 work done by 100 N force has to be equal to the kinetic energy
only then will the object stop
work= force X distance
800 = 100 X d
d= 8m
the body has already covered 2 m so in a further distance of
8-2= 6m the body will come to rest
Thumbs up plzz if this helped

an object A moving horizontally with kinetic energy of 800 J experiences a constant horizontal opposing force of 100 N while moving from point X to point Y where XY =2 m . what is the energy of A at Y ? In what further distance will A come to rest if this opposing force continues to act on it ?