an object A moving horizontally with kinetic energy of 800 J experiences a constant horizontal opposing force of 100 N while moving from point X to point Y where XY =2 m . what is the energy of A at Y ? In what further distance will A come to rest if this opposing force continues to act on it ?
1. work = force X distance= 100 X 2 = 200 N
.'. net energyof object = 800 - 200 = 600N
2.work done by 100 N force has to be equal to the kinetic energy. only then will the object stop.
work= force X distance
800 = 100 X d
the body has already covered 2 m so in a further distance of 8-2= 6m the body will come to rest.
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