An object is dropped from a height of 120m. The acceleration of the object is 10m/s^{2} downwards. Find the distance travelled by the object after (a)1s (b)2s and (c) 3s. What is the vilocity of the object after 3s?

** s = ut+1/2*a*t*t**

**The Object Is Dropped Hence Initial Velocity = 0**

**s = 1/2*10*t*t = 5*t*t**

**(a) Distance Travelled After 1 second = 5*1*1 = 5 m**

**(b) Distance Travelled After 2 Second = 5*2*2 = 20 m**

**(c) Distance Travelled After 3 Second = 5*3*3 = 45 m**

**(d) Velocity After 3 Second**

**v = u+at**

**Again Initial Velocity = 0**

**v = at**

**v = 10*3 = 30 m/sec**

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