an object is placed at a distance of 10 cm from a convex mirror of focal length 15cm. find the position and nature of the image.
Here,
Object distance, u = -10 cm
Focal length, f = 15 cm
Image distance = v
Now,
1/f = 1/v + 1/u
=> 1/15 = 1/v – 1/10
=> v = 6 cm
So, the image is located at a distance 6 cm from the mirror on the other side of the mirror.
Magnification, m = -v/u = 0.6
The image is virtual, erect and diminished.