An x molal solution of a compound in benzene has a molefraction =0.2.what is the value of x?

0.2 is the mole fraction of the solute in Benzene

Mole fraction of Benzene = 1-0.2 = 0.8

Molar mass of Benzene = 78 g/mol

Molality of solution = x

Molality can be found using the following formula:

m = (1000*x2) / (x1*M1)

x = (1000*0.2) / (0.8*78)

x = 3.205 moles/kg

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