Ans the following question.

Dear Student

V_{p} = 2400 V V_{s} = 240 V O u t p u t p o w e r = P_{S} = 240 W A s w e k n o w P = V I O u t p u t c u r r e n t I_{s} = \frac{P_{s}}{V_{s}} = \frac{240}{240} = 1 A \frac{I_{P}}{I_{S}} = \frac{V_{s}}{V_{P}} = \frac{240}{2400} = 0.1 I_{P} = 0.1 \times 1 = 0.1 A

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