answer plz fast

Solution
1. As the resistance increases, the current decreases, provided all other factors are kept constant.

2. Using Ohm's Law,
I = V/R
$$\begin{gathered} I\text{'} =\frac{2V}{R/2} \\ I\text{'} = 4I \end{gathered}$$

Hence the current becomes 4 times.

3. Ohm's law

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