Answer the both
Dear Student,
12.
Distance is greater than or equal to displacement.
Therefore, the numerical ratio of distance to displacement is always greater than or equal to one.
Distance/Displacement > 1 (option d).
13.
The acceleration is measure how fast the velocity is changes. We know that velocity is a vector quantity and change in velocity is due to change in magnitude as well as direction or both. Here, the boy is moving with constant speed but velocity changes and hence the motion of the boy is accelerating (option c).
Regards
12.
Distance is greater than or equal to displacement.
Therefore, the numerical ratio of distance to displacement is always greater than or equal to one.
Distance/Displacement > 1 (option d).
13.
The acceleration is measure how fast the velocity is changes. We know that velocity is a vector quantity and change in velocity is due to change in magnitude as well as direction or both. Here, the boy is moving with constant speed but velocity changes and hence the motion of the boy is accelerating (option c).
Regards