Answer this mathematics question fast Share with your friends Share 0 Lovina Kansal answered this We have,ab=3⇒b=3a ...(1)and,bc=6⇒3a×c=6 [using 1]⇒c=2a ...(2)and,ac=11⇒a(2a)=11 [using 2]⇒a2=112⇒a=112⇒a=2.35Put the value of a in (2), we getc=2×2.35⇒c=4.70Put the value of a in (1), we getb=32.35⇒b=1.27So, abc=2.35×4.70×1.27abc=14.02So, acoording to options you can consider 14.07 as the correct option. 0 View Full Answer
