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Answer to Q.6.

6. How much pressure will be felt by a gas balloon which at 100 m depth in a sea form sea level.

**[Pressure at ground level = ${10}^{5}Pa,g=9.8m/{s}^{2}$]**

(A) 100 Pa

(B) 98 Pa

(C) $9.8\times {10}^{5}$ Pa

(D) $1.08\times {10}^{6}$ Pa

Pressure at ground level, P

_{g}= 10

^{5}Pa

g= 9.8 m/s

^{2}

Therefore, pressure of the gas balloon at depth 100 m, P = hdg

where, h = depth; d = density; g = acceleration due to gravity

We know, Density of sea water = 1.03 x 10

^{3}kg/m

^{3}

Thus, P = 100 m x 1.03 x 10

^{3}kg/m

^{3}x 9.8 m/s

^{2}= 10.094 x 10

^{5}kg/ m s

^{2}= 1.0094 x 10

^{6}Pa or 1.08 x 10

^{6}Pa

So, the correct option is (d)

Regards

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