Answer to Q.6.
6. How much pressure will be felt by a gas balloon which at 100 m depth in a sea form sea level.
[Pressure at ground level = ]
(A) 100 Pa
(B) 98 Pa
(C) Pa
(D) Pa
Dear Student
Pressure at ground level, Pg = 105 Pa
g= 9.8 m/s2
Therefore, pressure of the gas balloon at depth 100 m, P = hdg
where, h = depth; d = density; g = acceleration due to gravity
We know, Density of sea water = 1.03 x 103 kg/m3
Thus, P = 100 m x 1.03 x 103 kg/m3 x 9.8 m/s2 = 10.094 x 105 kg/ m s2 = 1.0094 x 106 Pa or 1.08 x 106 Pa
So, the correct option is (d)
Regards
Pressure at ground level, Pg = 105 Pa
g= 9.8 m/s2
Therefore, pressure of the gas balloon at depth 100 m, P = hdg
where, h = depth; d = density; g = acceleration due to gravity
We know, Density of sea water = 1.03 x 103 kg/m3
Thus, P = 100 m x 1.03 x 103 kg/m3 x 9.8 m/s2 = 10.094 x 105 kg/ m s2 = 1.0094 x 106 Pa or 1.08 x 106 Pa
So, the correct option is (d)
Regards