# Answer to Q.6. 6. How much pressure will be felt by a gas balloon which at 100 m depth in a sea form sea level.[Pressure at ground level = ] (A) 100 Pa (B) 98 Pa (C) $9.8×{10}^{5}$ Pa (D) $1.08×{10}^{6}$ Pa

Dear Student

Pressure at ground level, Pg = 105 Pa
g= 9.8 m/s2

Therefore, pressure of the gas balloon at depth 100 m, P = hdg

where, h = depth;    d = density;          g = acceleration due to gravity

We know, Density of sea water = 1.03 x 103 kg/m3

Thus, P = 100 m x 1.03 x 103 kg/m3 x 9.8 m/s2 = 10.094 x 105 kg/ m s2 = 1.0094 x 106 Pa or 1.08 x 106 Pa

So, the correct option is (d)

Regards

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