Assign the hybridization, shape and magnetic moment of K3[Cu(CN)4] :
(1) | sp3, tetrahedral, 1.73 B.M. |
(2) | dsp2, square planar, 1.73 B.M. |
(3) | sp3, tetrahedral, diamagnetic |
(4) | dsp2, square planar, 2.44 B.M. |
Cu in K3[Cu(CN)4] exists in +1 oxidation state, with electronic configuration of 3d10. The hybridisation will be sp3 as Cu forms 4 coordinate bond with 4 CN- ligands, thereby the geometry will be tetrahedral and it will be diamagnetic due to no unpaired electron. Thus, the correct answer is : (3). sp3, tetrahedral, diamagnetic