Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃?

(At. mass Ba= 137).

According to the given equation,

1 mole (197 g) of Barium carbonate gives 1 mole (22.4 L) of Carbon-di-oxide.

Therefore, 9.85 g of Barium carbonate will give (22.4x9.85) / 197 = 1.12 L of Carbon-di-oxide gas at S.T.P