At a point along a horizontal pipe, the cross section area is 12 cm? and streamline flow of water with velocity 2ms and pressure 3000 Pais flowing through it. The velocity of water at point where cross-sectioned area is 6 cm? is equal to

Solution:
Here we shall first use the continuity equation  av = a'v'  where  a and a' are cross-sectional areas at points 1 and 2 respectively and  v and v' are the velocities of fluid at points 1 and 2 respectively  so,  a =12 cm2  =12×10-4m2v = 2 m/s  a' = 6 cm2  =6×10-4m2  now, as  v' = 12×10-46×10-4×2so,   v' = 4 m/s

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