b)A 200 WATT BULB EMITS MONOCHROMATIC LIGHT OF WAVELENGTH 500nm. Calculate the no.of photons emitted per second by the bulb. (3 marks)

h = 6.626 x10 ^ -34

c = 3x10^8 m/s

λ = 500 nm = 5x10^-7 m

 

Energy of one photon:

Ephoton = hc /λ

Ephoton = (6.626x10^-34*3x10^8)/5x10^-7 = 3.975x10^-33J

 

Bulb emits: 200 W = 200 J/s; A power of 200 W means 200 joules per second, so the number of photons is

 

Photons / s = 200 J/s / Ephoton

  = 200 J/s /3.975x10^-33J

   = 50.31*10^33

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