BOARD QUESTIONS: Do give correct answer of the 7th question."DO NOT SEND ANSWERS THROUGH LINKS" Q.7. Find the value of k, for which the quadratic equation k - 2 x 2 - 2 2 k - 3 x + 5 k - 6 = 0 has real and equal roots. [Ans. k = 1, 3] Share with your friends Share 0 Varun Rawat answered this The given equation is, k-2x2 - 22k-3x + 5k-6 = 0Now, a = k-2; b = -22k-3; c = 5k-6Now, D = b2 - 4ac=42k-32 - 4 k-25k-6=44k2 + 9 - 12k - 45k2-16k+12=16k2 + 36 - 48k - 20k2 + 64k - 48=-4k2 + 16k - 12Now, for real and equal roots, D = 0⇒-4k2 + 16k - 12 = 0⇒-4k2 - 4k + 3 = 0⇒k2 - 4k + 3 = 0⇒k2 - 3k - k + 3 = 0⇒kk - 3 - 1k - 3 = 0⇒k - 1k - 3 = 0⇒k - 1 = 0 and k - 3 = 0⇒k = 1 and k = 3 0 View Full Answer