BOARD QUESTIONS: Do give correct answer of the 7th question."DO NOT SEND ANSWERS THROUGH LINKS"
Q.7. Find the value of k, for which the quadratic equation k - 2 x 2 - 2 2 k - 3 x + 5 k - 6 = 0 has real and equal roots.
[Ans. k = 1, 3]

The given equation is,     k-2x2 - 22k-3x + 5k-6 = 0Now, a = k-2; b = -22k-3; c = 5k-6Now, D = b2 - 4ac=42k-32 - 4 k-25k-6=44k2 + 9 - 12k - 45k2-16k+12=16k2 + 36 - 48k - 20k2 + 64k - 48=-4k2 + 16k - 12Now, for real and equal roots,        D = 0-4k2 + 16k - 12 = 0-4k2 - 4k + 3 = 0k2 - 4k + 3 = 0k2 - 3k - k + 3 = 0kk - 3 - 1k - 3 = 0k - 1k - 3 = 0k - 1 = 0    and    k - 3 = 0k = 1   and  k = 3

  • 0
What are you looking for?