Bob wants to cover the floor of a room 3m wide and 4.5m long by squared tiles. If each square tile is of side 0.75m,find the cost of flooring the room at the rate of ₹4.50 per tile. Please answer fast , test soon.

And width of the floor of a room = 3 m

So area of the floor of a room = $4.5\mathrm{m}\times 3\mathrm{m}=13.5{\mathrm{m}}^{2}$

Now side of each square tile = 0.75 m

So area of each square tile = ${\left(0.75\mathrm{m}\right)}^{2}=0.;5625{\mathrm{m}}^{2}$

So total number of square tiles needed to cover the floor = $\frac{\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{floor}}{\mathrm{are}\mathrm{of}\mathrm{each}\mathrm{square}\mathrm{tile}}=\frac{13.5}{0.5625}=24$

Cost each tile = Rs.4.50

So total cost of flooring the room = $24\times 4.50$ = Rs.108

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