Calculate mass of 3.011 X 10 23no of nitrogen atoms ( atomic mass of N = 14 u)

Given number of nitrogen atoms = 3.011 X 1023

Number of moles = Number of particles / Avogadro number

= 3.011 X 1023 / 6.023*1023

= 0.5 moles

So, Mass = moles * molar mass

= 0.5 * 14

= 7g

So, 7g is the mass of 3.011 X 1023 number of nitrogen atoms.

  • 35

 No.of atoms / Avogadro Number = No.of Mole

3.011 * 1023 / 6.022 * 1023 = 1/2

No.of mole = given mass/ molar mass

1/2 = x/ 28

x = 14 u

  • 6

 Atomic mass of nitrogen = 14 u

Mass of 1 mole ( 6.022 X 1023 ) = 14 g

Mass of  3.011 X 1023  atoms of nitrogen = Mass of ( 6.022 X 1023)/2 atoms of nitrogen = (14/2)g = 7g

ANSWER+ 7 g .

  • 3

 Atomic mass of nitrogen = 14 u

Mass of 1 mole ( 6.022 X 1023 ) = 14 g

Mass of 3.011 X 1023 atoms of nitrogen = Mass of ( 6.022 X 1023)/2 atoms of nitrogen = (14/2)g = 7g

ANSWER= 7 g .

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