Calculate pH of the solution obtained by mixing 100cm3of solution with pH=3 with 400cm3 of solution with pH=4.

First find the molarity of the resulting solutionV1M1 + V2M2 = V3M3100 ×1×10-3 + 400 ×1×10-4 = 500 × M3M3 = 100 ×1×10-3 + 400 ×1×10-4500 = 140 × 10-3500 = 0.28 × 10-3 MpH= - log H+    = - log  0.28 × 10-3      = 3 log 10 - log 0.28      = 3 - (-0.5528)     = 3.5528 

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