Calculate the equilibrium constant of the reaction at 298 K .
Mg(s) + 2Ag+(aq) --> Mg2+(aq) +2Ag(s); E⁰ _cell=+3.16 V

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Calculate the equilibrium constant of the reaction at 298 K
Mg(s) + 2Ag+(aq) --> Mg2+(aq) +2Ag(s); E0
cell=+3 16 V

Vartika Jain · Accepted Answer

Dear Student,

∆G°=-nFE°celland, ∆G°=-RTlnKeqTherefore, nFE°cell=RTlnKeqor, lnKeq=nFE°cellRTHere, n=2   (as 2 electrons are involved)F=96500 E°cell=3
16 VR=8
314 JK-1mol-1T=298 Kor, lnKeq=2×96500×3
168 314×298=246 16or, Keq= e246 16=8 05

Calculate the equilibrium constant of the reaction at 298 K . Mg(s) + 2Ag+(aq) --> Mg2+(aq) +2Ag(s); E0 cell=+3.16 V

Calculate the equilibrium constant of the reaction at 298 K .
Mg(s) + 2Ag+(aq) --> Mg2+(aq) +2Ag(s); E⁰ _cell=+3.16 V