Calculate the escape velocity for an atmospheric particle 1600km above the earth's surface,Given;The radius of earth is 6400km and acceleration due to gravity on the surface of earth is 9.8. Share with your friends Share 11 Abhay Kumar answered this We know that bindin energy of particle on the surface of earth is GMm/R+h.If this much energy is supplied in form of kinetic energy the body will escape out of the gravitaional field of earth.v = 2gRputting the valuesv = 2*9.8*(6400+1600)*10-3 km/s= 12.52 km/sec -26 View Full Answer Guru Prasad Singh answered this Given, Re=6400km= 6.4*106 m r=1600km= 1.6*106 mg= 9.8m/s2Hence Escape Velocity =√2*gR= Ve=√2*g*(Re+r)= Ve=√2*9.8*(6.4+1.6)*106= Ve= 12.5 *103 m/s= 12.5 km/sHence the Escape Velocity in the given condition is 12.5 km/s 8