. Calculate the heat for the overall reaction: Mg(s) + 1/2O2 → MgO(s) given the heats of reaction below: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) ∆H = –143 kJ MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(g) ∆H = –216 kJ H2(g) + 1/2O2 → H2O(l) ∆H = –285 kJ (A) –644 kJ (B) –212 kJ (C) +644 kJ (D) –74 kJ (E) +74 kJ

Dear Student,

(i) Mg(s) +  2HCl(aq)    MgCl2(aq)  + H2(g)                 Hi=-143 kJ(ii) MgO(s) +  2HCl(aq)    MgCl2(aq)  + H2O(g)          Hii=-216 kJ(iii) H2(g) + 12O2(g)    H2O(l)                                            Hiii=-285 kJThe required equation is,(iv)Mg(s) +12O2(g)  MgO(s)                                     H?The above equation can be obtained as, (iv)=[(i)-(ii)]+(iii)H=[Hi-Hii]+Hiii      =[-143-(-216)]+(-285)      =73-285      =-212 kJHence, correct answer is (B)

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